1x^2+2x=49

Solution for 1x^2+2x=49 equation:

1x^2+2x=49

We move all terms to the left:

1x^2+2x-(49)=0

We add all the numbers together, and all the variables

x^2+2x-49=0

a = 1; b = 2; c = -49;
Δ = b2-4ac
Δ = 22-4·1·(-49)
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10\sqrt{2}}{2*1}=\frac{-2-10\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10\sqrt{2}}{2*1}=\frac{-2+10\sqrt{2}}{2}
$